Question

c语言咋错了？

#include <stdio.h>
void main()
{char a[11]={"i"," ","l","o","v","e"," ","y","o","u",\0};
int b=0;
for(b=0,b<=10,b++)
{printf("%c",a[b]);
}
printf("\n");
}

D:\Microsoft Visual Studio\MyProjects\2233\233.cpp(5) : error C2143: syntax error : missing ';' before ')'
执行 cl.exe 时出错.

233.exe - 1 error(s), 0 warning(s)

Answer 1

有两种错误：

1、char a[11]={"i"," ","l","o","v","e"," ","y","o","u",\0};

{}里面的为初始值，应该是字符，用单引号，不能用双引号。双引号就是字符串了，所需的存储空间就不够用了。

2、for(b=0,b<=10,b++)

for循环中写错了，应该是分号，而不是逗号.

Answer 2

error C2143: syntax error : missing ';' before ')'
这个提示很明显呀，语法错误，在括号前缺少分号,for语法是这样的：
for(int i=0;i<100;i++)
printf("%d ",2*i+1);

Answer 3

for循环中写错了，应该是分号，而不是逗号。
for 循环的一般形式为：
for(表达式1; 表达式2; 表达式3){
语句块
}