Question

求由e^(x+y)+sin(xy)=x确定的隐函数y=f(x)导数或微分

Answer 1

对x求导有：
e^(x+y)*(1+y')+cos(xy)(y+xy')=1
[e^(x+y)+cos(xy)x]y'=1-e^(x+y)-y*cos(xy)
y'=[1-e^(x+y)-y*cos(xy)] / [e^(x+y)+cos(xy)x]