分解因式(x²-6x+9/x²-9)+(x³-4x²+4x/x²+3x?
1个回答
展开全部
原式=(x-3)²/(x+3)(x-3)+x(x²-4x+4)/x(x+3)
=(x-3)/(x+3)+(x²-4x+4)/(x+3)
=(x-3+x²-4x+4)/(x+3)
=(x²-3x+1)/(x+3),3,额,真不会,讨厌那个东西,烦死了,2,(x²-6x+9/x²-9)+(x³-4x²+4x/x²+3x)
=(x-3)²/(x-3)(x+3)+x(x-2)²/x(x+3)
=(x-3)/(x+3)+(x-2)²/(x+3)
=(x-3+x²-4x+4)/(x+3)
=(x²-3x+1)/(x+3),1,分解因式(x²-6x+9/x²-9)+(x³-4x²+4x/x²+3x)
快点啊,
=(x-3)/(x+3)+(x²-4x+4)/(x+3)
=(x-3+x²-4x+4)/(x+3)
=(x²-3x+1)/(x+3),3,额,真不会,讨厌那个东西,烦死了,2,(x²-6x+9/x²-9)+(x³-4x²+4x/x²+3x)
=(x-3)²/(x-3)(x+3)+x(x-2)²/x(x+3)
=(x-3)/(x+3)+(x-2)²/(x+3)
=(x-3+x²-4x+4)/(x+3)
=(x²-3x+1)/(x+3),1,分解因式(x²-6x+9/x²-9)+(x³-4x²+4x/x²+3x)
快点啊,
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询