e^xy=cos(x+y)求导
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e^(xy)=cos(x+y)
d/dx[e^(xy)]=d/dx [cos(x+y)]
e^(xy). ( xdy/dx + y)= -sin(x+y) .( 1+ dy/dx)
[xe^(xy) + sin(x+y)] dy/dx = -sin(x+y) - ye^(x+y)
dy/dx = [-sin(x+y) - ye^(x+y)]/[xe^(xy) + sin(x+y)]
d/dx[e^(xy)]=d/dx [cos(x+y)]
e^(xy). ( xdy/dx + y)= -sin(x+y) .( 1+ dy/dx)
[xe^(xy) + sin(x+y)] dy/dx = -sin(x+y) - ye^(x+y)
dy/dx = [-sin(x+y) - ye^(x+y)]/[xe^(xy) + sin(x+y)]
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