Question

(x-2)²=(2x+3)²怎么算?

help me

Answer 1

直接去掉平方就是两边的绝对值相等
所以
x-2=(2x+3)
或者x-2=-(2x+3)

即x=-5或-5/3

Answer 2

(x-2)²=(2x+3)²
(x-2)²-(2x+3)²=0
(x-2+2x+3)(x-2-2x-3)=0
(3x+1)(-x-5)=0
3x+1=0或-x-5=0
x1=-1/3
x2=-5

Answer 3

(x-2)²=(2x+3)²
(x-2)²-(2x+3)²=0
(x-2+2x+3)(x-2-2x-3)=0
(3x+1)((-x-5)=5

3x+1=0 x=-1/3
-x-5=0 x=-5

解得：x=-1/3或者x=-5

Answer 4

(x-2)²=(2x+3)²
x-2=2x+3
则x-2=2x+3或x-2=-2x-3
x1=-5，x2=-1/3

Answer 5

(2x+3)²-(x-2)²=0
(2x+3-x+2)(2x+3+x-2)=0
(x+5)(3x+1)=0
x=-5,x=-1/3