
2个回答
展开全部
解:
1/x-1/y=3
(y-x)/xy=3
y-x=3xy
即x-y=-3xy
(2x+3xy-2y)/(x+2xy-y)
[2(x-y)+3xy]/[(x-y)+2xy]
=(-6xy+3xy)/(-3xy+2xy) (注:把x-y=-3xy代入得)
=3
1/x-1/y=3
(y-x)/xy=3
y-x=3xy
即x-y=-3xy
(2x+3xy-2y)/(x+2xy-y)
[2(x-y)+3xy]/[(x-y)+2xy]
=(-6xy+3xy)/(-3xy+2xy) (注:把x-y=-3xy代入得)
=3
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询