因式分解 2x²-x-4=? x²-3xy-y²=
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2X²-X-4
=2(X²-1/2X-2)
=2［(X-1/4)²-(√33/4)²］
=2(X-1/4+√33/4)(A-1/4-√33/4)
X²-3XY-Y²
=(X-3/2Y)²-(√13/2Y)²
=(X-3/2Y+√13/2Y)(X-3/2Y-√13/2)
=［(X+(-3+√13)/2Y］［X+(-3-√13)/2Y］
=2(X²-1/2X-2)
=2［(X-1/4)²-(√33/4)²］
=2(X-1/4+√33/4)(A-1/4-√33/4)
X²-3XY-Y²
=(X-3/2Y)²-(√13/2Y)²
=(X-3/2Y+√13/2Y)(X-3/2Y-√13/2)
=［(X+(-3+√13)/2Y］［X+(-3-√13)/2Y］
追问
答案怎么那么长
追答
写成分数的式子。
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