Question

fastJson能不能将int类型转换为String类型

Answer 1

/**
* json特殊操作
* <p>
*
* @author 宋汝波
* @date 2014年11月24日
* @version 1.0.0
*/
public class JsonUtil {
private static final Logger logger = LoggerFactory.getLogger(JsonUtil.class);
/**
* 对序列化的Long类型进行特殊处理,避免位数过大导致和js精度的丢失,只用于向页面发送json数据时使用
*/
static ObjectSerializer longSerializer = new ObjectSerializer() {

@Override
public void write( JSONSerializer serializer, Object object, Object fieldName, Type fieldType )
throws IOException {
SerializeWriter out = serializer.getWriter();
if ( object == null ) {
if ( out.isEnabled(SerializerFeature.WriteNullNumberAsZero) ) {
out.write('0');
} else {
out.writeNull();
}
return;
}
out.writeString(object.toString());
}

};

/**
* 对Long型兼容js的json串
* <p>
*
* @param object
* 对象
* @return json字符串
*/
public static final String toCompatibleJSON( Object object, String format ) {
SerializeWriter out = new SerializeWriter();
try {
//此处必须new一个SerializeConfig,防止修改默认的配置
JSONSerializer serializer = new JSONSerializer(out, new SerializeConfig());
serializer.getMapping().put(Long.class, longSerializer);
if ( format != null ) {
serializer.getMapping().put(Date.class, new SimpleDateFormatSerializer(format));
}
serializer.write(object);
return out.toString();
} finally {
out.close();
}
}

public static final String toCompatibleJSON( Object object ) {
return toCompatibleJSON(object, null);
}

public static void main( String[] args ) {
logger.debug(toCompatibleJSON(new Date(), "yyyy-MM-dd"));
logger.debug(toCompatibleJSON(new Date(), null));
}
}