Question

如何在 Python 中模拟 post 表单来上传文件

Answer 1

近有个将文件上传到内部web服务器上的任务，于是参考了网上部分源码用python写了这个小程序，代码如下：

[python] view plain copy
#coding:utf-8
'''''
Created on 2015.3.19
@author: damofy
'''
import os
import time
import sys
import urllib2

'''''
filename 待上传的文件
fieldname 表单域中的name属性
'''
def CreateBody(filename, fieldname, strBoundary):
bRet = False
sData = []
sData.append('--%s' % strBoundary)
#'Content-Disposition: form-data; name="uploadfile"; filename="XX-Net-1.3.6.zip"'
sData.append('Content-Disposition: form-data; name="%s";' % fieldname + 'filename="%s"' % os.path.basename(filename))
sData.append('Content-Type: %s\r\n' % 'application/octet-stream')

try:
pFile = open(filename, 'rb')
sData.append(pFile.read())
sData.append('--%s--\r\n' % strBoundary)
bRet = True
finally:
pFile.close()

return bRet, sData

def uploadfile(http_url, filename, fieldname):
if os.path.exists(filename):
filesize = os.path.getsize(filename)
print('file:' + filename + ' is %d bytes!' % filesize)
else:
print('file:' + filename + ' isn\'t exists!')
return False

strBoundary = '---------------------------%s' % hex(int(time.time() * 1000))
bRet, sBodyData = CreateBody(filename, fieldname, strBoundary)
if True == bRet:
http_body = '\r\n'.join(sBodyData)
stReq = urllib2.Request(http_url, http_body)
stReq.add_header('User-Agent','Mozilla/5.0')
stReq.add_header('Content-Length:', '%d' % filesize)
stReq.add_header('Content-Type', 'multipart/form-data; boundary=%s' % strBoundary)
resp = urllib2.urlopen(stReq, timeout=5)
# get response
msg = resp.read()
print("Response content:\n" + msg)
else:
print("CreateBody failed!")

return bRet

if __name__ == '__main__':

if len(sys.argv) > 2:
http_url = sys.argv[1]
filename = sys.argv[2]
else:
print('python upload.py http://10.20.131.23/upload ./test.dat')
sys.exit()

# 参数3 "uploadfile" 是post表单中的name属性，需要与服务端保持一致
uploadfile(http_url, filename, 'uploadfile')