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a=2^(4/3) , b=3^(2/3), c=25^(1/3)
/
c=25^(1/3) = 5^(2/3) > 3^(2/3) =b
=> c>b
/
c=25^(1/3) = (√5)^(4/3) > 2^(4/3) = a
=> c>a
/
b=3^(2/3) = (√3)^(4/3) < 2^(4/3) =a
ie
b<a<c
ans : B
/
c=25^(1/3) = 5^(2/3) > 3^(2/3) =b
=> c>b
/
c=25^(1/3) = (√5)^(4/3) > 2^(4/3) = a
=> c>a
/
b=3^(2/3) = (√3)^(4/3) < 2^(4/3) =a
ie
b<a<c
ans : B
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