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第三题:
1/(1 + 2) + 1/(1 + 2 + 3) + .... + 1/(1 + 2 + 3 + ... + 100)
= 2/(2*3) + 2/(3*4) + .... + 2/(100*101)
= 2*(1/2 - 1/3) + 2*(1/3 - 1/4) + ... + 2*(1/100 - 1/101)
=2*(1/2 - 1/101)
= 1 - 2/101
= 99/101
第四题:
3-5+7-9+11-13...+1995-1997+1999
=(3-5)+(7-9)+(11-13)...+(1995-1997)+1999
=-2 * 499 + 1999
=-2 * 500 + 2 + 1999
=-1000 + 1999 + 2
=999 + 2
=1001
1/(1 + 2) + 1/(1 + 2 + 3) + .... + 1/(1 + 2 + 3 + ... + 100)
= 2/(2*3) + 2/(3*4) + .... + 2/(100*101)
= 2*(1/2 - 1/3) + 2*(1/3 - 1/4) + ... + 2*(1/100 - 1/101)
=2*(1/2 - 1/101)
= 1 - 2/101
= 99/101
第四题:
3-5+7-9+11-13...+1995-1997+1999
=(3-5)+(7-9)+(11-13)...+(1995-1997)+1999
=-2 * 499 + 1999
=-2 * 500 + 2 + 1999
=-1000 + 1999 + 2
=999 + 2
=1001
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