Question

mysql 查询结果求和

SELECT i.uid,deposit+ddeposit+money as allmoney FROM pw_memberinfo i LEFT JOIN pw_members m ON m.uid=i.uid LEFT JOIN pw_memberdata d ON i.uid=d.uid sum(allmoney) where deposit+ddeposit+money>2000;

怎么求 allmoney字段结果的合

sum() 应该加在什么地方？

Answer 1

1、创建三张测试表，

create table pw_memberinfo(uid int, name varchar(20));

create table pw_members(companyid int, uid int);

create table pw_memberdata(uid int, deposit int, ddeposit int, money int);

2、三张表，分别插入测试数据，

insert into pw_members values(1, 1);

insert into pw_members values(1, 2);

insert into pw_members values(1, 3);

insert into pw_memberinfo values(1, 'name_1');

insert into pw_memberinfo values(2, 'name_2');

insert into pw_memberinfo values(3, 'name_3');

insert into pw_memberdata values(1,30,50,150);

insert into pw_memberdata values(2,77,50,12);

insert into pw_memberdata values(3,44,50,82);

3、查看pw_memberdata表中的记录，select * from pw_memberdata t，

4、编写sql语句，

select * from (SELECT i.uid, sum(deposit+ddeposit+money) as allmoney 

FROM pw_memberinfo i 

LEFT JOIN pw_members m ON m.uid=i.uid 

LEFT JOIN pw_memberdata d ON i.uid=d.uid 

group by i.uid

) t where allmoney>200

Answer 2

SELECT i.uid,deposit+ddeposit+money as allmoney FROM

------------->

SELECT i.uid,sum(deposit+ddeposit+money) as allmoney FROM

另外,因为你是多个表的左联接,考虑到有NULL记录的存在,建议你用函数ifnull处理下,避免由于NULL而造成结果有误,最终改成这样:

SELECT i.uid,sum(ifnull(deposit,0)+ifnull(ddeposit,0)+ifnull(money,0)) as allmoney
FROM pw_memberinfo i LEFT JOIN pw_members m ON m.uid=i.uid LEFT JOIN pw_memberdata d ON i.uid=d.uid
where ifnull(deposit,0)+ifnull(ddeposit,0)+ifnull(money,0)>2000;

Answer 3

SELECT i.uid,sum(deposit+ddeposit+money) as allmoney

Answer 4

我是来顶 vinson_shen 的答案的

Answer 5

来顶顶，不懂。。嘻嘻