Question

C#编程将XML文件读取后绑定到一个Treeview控件中

<Student>
<Name>罗志祥</Name>
<Age>20</Age>
<Hobby>唱歌</Hobby>
<Name>杨丞琳</Name>
<Age>22</Age>
<Hobby>跳舞</Hobby>
</Student>

Answer 1

using System.Xml;

.
.
.

XmlDocument doc = new XmlDocument();
doc.Load("XMLFile1.xml"); //我是把xml放到debug里面了.你的路径就随便啦.不过这样方便一些...
XmlNode node = doc.DocumentElement;
TreeNode tree = null; ;
foreach (XmlNode node1 in node.ChildNodes)
{

if (node1.Name == "Name")
{
tree = new TreeNode();
tree.Text = node1.InnerText;
treeView1.Nodes.Add(tree);
}
else
{
TreeNode tree1 = new TreeNode();
tree1.Text = node1.InnerText;
tree.Nodes.Add(tree1);
}

}

good luck;;;

Answer 2

你可以把xml文件读取到xsd里面，然后对xsd操作，取值加载到treeview树！

Answer 3

replace（“‘”，“’‘”）之后就转化成string类型

Answer 4

可以直接读阿

Answer 5

//单击按钮键
private void butAdd_Click(object sender, EventArgs e)
{
InitSonger();//方法
}
private void InitSonger()
{
//xml文档
XmlDocument doc = new XmlDocument();
//加载XML文件
doc.Load("Songer.xml");
//读取根节点
XmlNode root = doc.DocumentElement;
TreeNode tree = null;
foreach (XmlNode node in root.ChildNodes)
{
if (node.Name=="Name")
{
tree = new TreeNode();
tree.Text = node.InnerText;
tvSonger.Nodes.Add(tree);
}
else
{
TreeNode tree1 = new TreeNode();
tree1.Text = node.InnerText;
tree.Nodes.Add(tree1);
}
}

}