Question

大家帮我看看这个java小程序哪里出错了~~

public class CountWords{
public static void main(String args[]){
char words[] = "Java is an object oriented programming language";
int counterWords = 0, counterNull = 0;
for( int i=0; i< words.length()-1; i++)
{
if( words[i].equals(' '))
{ counterNull++; }
else { counterWords++; }
}
System.out.println("words is " + counterWords);
System.out.println("AvgWords is " +(double)counterWords/counterNull);
}
}
用记事本写的，将就将就下哈
哎，学了C++，现在学Java,有些不习惯

Answer 1

public static void main(String args[]) {
char[] words = "Java is an object oriented programming language".toCharArray();
int counterWords = 0, counterNull = 0;
for (int i = 0; i < words.length - 1; i++) {
if (words[i] == ' ') {
counterNull++;
} else {
counterWords++;
}
}
System.out.println("words is " + counterWords);
System.out
.println("AvgWords is " + (double) counterWords / counterNull);
}

错误除了楼上朋友说的以外还有几个地方
1.length是属性，不是方法，所以不需要length()
2.char 是原始类型，没有equals方法，所以只需要用==做比较就好，比较' '中间要一个空格，才可以，不能直接''。

Answer 2

char words[] = "Java is an object oriented programming language";
你把一个字符串赋值给一个字符数组？

改成String words[] = {"Java is an object oriented programming language"};

先找出这个很明显的毛病，是否还有其他的毛病没仔细看