Question

Lg5*Lg8000+（Lg2√3^2+Lg0.06-Lg6=?

Answer 1

lg5*lg8000+（lg2^根号3）^2+lg0.06-lg6
=lg5*(lg8+lg1000)+(√3*lg2)^2+lg(6/100)-lg6
=lg5*(3lg2+3)+3*(lg2)^2+lg[(6/100)/6]
=3lg2*lg5+3lg5+3(lg2)^2+lg(1/100)
=3lg2(lg2+lg5)+3lg5+lg10^(-2)
=3lg2*lg10+3*lg5-2
=3lg2+3lg5-2
=3(lg2+lg5)-2
=3*1-2
=1

Answer 2

lg5=1-lg2
lg8000=lg8+3=3lg2+3=3(1+lg2)
(lg2^根三)^2=(根三lg2)^2=3(lg2)^2
lg0.06=lg6-2
所以
lg5·lg8000+(lg2^根三)^2+lg0.06+lg6
=(1-lg2)[3(1+lg2)]+3(lg2)^2+lg6-2+lg6
=3-3(lg2)^2+3(lg2)^2+2lg6-2
=1+2lg6
答案是1+2lg6
lg5·lg8000+(lg2^根三)^2+lg0.06+lg6
_____________________~~~~~~~~~~~~~
你是不是把这两处的运算符号写错了一位?
如果没有写错,答案是1+2lg6
可以查到lg6=0.7781
1+2lg6=2.5562
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