Question

又一道分解因式的问题……求高手破

-x²(y-xy²-y³-1+xy-y²)-y(xy-x)

Answer 1

-x"( y - xy" - y"' - 1 + xy - y" ) - y( xy - x )
= x"( - y + xy" + y"' + 1 - xy + y" ) - xy" + xy
= x( x + xy"' + x"y" + xy" - xy - x"y ) + x( y - y" )
= x( x + xy" + xy"' + x"y" + y - y" - xy - x"y )

xy - x"y" + y" - xy"' - x + x"y - y + xy"
= xy( 1 - xy ) + y"( 1 - xy ) - x( 1 - xy ) - y( 1 - xy )
= y( 1 - xy )( x + y ) - ( 1 - xy )( x + y )
= ( 1 - xy )( x + y )( y - 1 )

Answer 2

=-x2y+x3y2+x2y3+x2-x3y+x2y2-xy2+xy
=-x(xy-x2y2-xy3-x+x2y-xy2+y2-y)
[答案就是这个。剩下的不可分解！]
~~~~~~~~~~~求采纳~~~~~~~~~~~~~

追问

不好意思……把不同的两道题重叠在一起了……应该是：
xy-x2y2+y2-xy3-x+x2y-y+xy2

追答

楼上回答的挺好的。。过程也没问题

Answer 3

=-x2y+x3y2+x2y3+x2-x3y+x2y2-xy2+xy
=-x(xy-x2y2-xy3-x+x2y-xy2+y2-y)

追问

不好意思……把不同的两道题重叠在一起了……应该是：
xy-x2y2+y2-xy3-x+x2y-y+xy2