Question

因式分解4m^2+4m+1

要有过程！因式分解：9a^2-24ab+16b^2、-m^2-m-1/4

Answer 1

这是一个完全平咐扮方式啊！耐简亮
4m^2+4m+1
=(2m)^2 + 2 * 2m*1 + 1^2
=(2m+1)^2

9a^2-24ab+16b^2

=(3a)^2 + 2*(3a)*(-4b)+(4b)^2
=(3a-4b)^2

-m^2-m-1/昌宽4

= -1 * ( m^2 + 2*(1/2)*m + (1/2)^2 )
= -(m+1/2)^2

追问

又补充了一个，帮忙解一下，谢谢

追答

已经解答

Answer 2

4m^2+4m+1=(2m+1)^2

追问

又补充了一个，帮忙解一下，谢谢

追答

9a^2-24ab+16b^2
=(3a-4b)^2

-m^2-m-1/4
=-(m^2+m+1/4)
=-(m+1/2)^2

Answer 3

=(2m)²+2×2m×1+1²
=(2m+1)²

追问

又补充了一个，帮忙解一下，谢谢

追答

9a^2-24ab+16b^2
=(3a)²-2× 3a×4b+(4b)²
=(3a-4b)²

-m^2-m-1/4
=-(m²+m+1/4)
=-(m+1/2)²

Answer 4

4m^2+4m+1
=（2m)²+2×2m×1+1²
=(32m+1)²

追问

又补充了一个，帮忙解一下，谢谢

追答

4m^2+4m+1
=（2m)²+2×2m×1+1²
=(2m+1)²
9a^2-24ab+16b^2
=（3a)²-2×3a×4b+(4b)²
=(3a-4b)²
-m^2-m-1/4
=-(m²+m+1/4)
=-(m+1/2)²

Answer 5

=（2m+1）^2