用因式分解的方法
2个回答
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9( x - 2 )" = 4( x + 1 )"
[ 3( x - 2 ) ]" - [ 2( x + 1 ) ]" = 0
( 3x - 6 )" - ( 2x + 2 )" = 0
( 3x - 6 - 2x - 2 )( 3x - 6 + 2x + 2 ) = 0
( x - 8 )( 5x - 4 ) = 0
解方程得
x1 = 8 ,
x2 = 4/5
( x - 3 )" + 4x( x - 3 ) = 0
( x - 3 )( x - 3 + 4x ) = 0
( x - 3 )( 5x - 3 ) = 0
解方程得
x1 = 3 ,
x2 = 3/5
[ 3( x - 2 ) ]" - [ 2( x + 1 ) ]" = 0
( 3x - 6 )" - ( 2x + 2 )" = 0
( 3x - 6 - 2x - 2 )( 3x - 6 + 2x + 2 ) = 0
( x - 8 )( 5x - 4 ) = 0
解方程得
x1 = 8 ,
x2 = 4/5
( x - 3 )" + 4x( x - 3 ) = 0
( x - 3 )( x - 3 + 4x ) = 0
( x - 3 )( 5x - 3 ) = 0
解方程得
x1 = 3 ,
x2 = 3/5
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