Question

system.web.ui.page.user是属性,但此处被当作类型来使用

DataTable tbScratchCard = new DataTable();

DataColumn colSerialNumber = new DataColumn();
colSerialNumber.DataType = System.Type.GetType("System.Int32");
colSerialNumber.ColumnName = "serialNumber";

DataColumn colType = new DataColumn();
colType.DataType = System.Type.GetType("System.String");
colType.ColumnName = "type";

DataColumn colModifiedTime = new DataColumn();
colModifiedTime.DataType = System.Type.GetType("System.DateTime");
colModifiedTime.ColumnName = "modifiedTime";

DataColumn colModifiedName = new DataColumn();
colModifiedName.DataType = System.Type.GetType("System.String");
colModifiedName.ColumnName = "modifiedName";

DataColumn[] cols = { colSerialNumber, colType, colModifiedTime, colModifiedName };

tbScratchCard.Columns.AddRange(cols);

tbScratchCard.Rows.Add(tbScratchCard.NewRow());
tbScratchCard.Rows[0]["serialNumber"] = tbScratchCard.Rows.Count - 1;
tbScratchCard.Rows[0]["modifiedTime"] = DateTime.Now;
tbScratchCard.Rows[0]["modifiedName"] = ((User)Session["user"]).AccountName;
ViewState["tbCategory"] = tbScratchCard;

gvFrontendTypeSetting.DataSource = tbScratchCard;
gvFrontendTypeSetting.DataBind();

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Answer 1

多调试下啊