
1×2×3×4分之3+2×3×4×5分之3+……+17×18×19×20分之3
2014-08-25
展开全部
1/n(n+1)(n+2)(n+3)
=1/2{1/n - 1/(n+3) + 1/(n+2)-1/(n+1)}
1×2×3×4分之3+2×3×4×5分之3+……+17×18×19×20分之3
=3/2*(1+1/3-1/2-1/4 +1/2+1/4-1/3-1/5+...+1/17+1/19-1/18-1/20)
=3/2*(1-1/20)
=3/2*19/20
=57/40
【参考:http://zhidao.baidu.com/question/186456720.html】
=1/2{1/n - 1/(n+3) + 1/(n+2)-1/(n+1)}
1×2×3×4分之3+2×3×4×5分之3+……+17×18×19×20分之3
=3/2*(1+1/3-1/2-1/4 +1/2+1/4-1/3-1/5+...+1/17+1/19-1/18-1/20)
=3/2*(1-1/20)
=3/2*19/20
=57/40
【参考:http://zhidao.baidu.com/question/186456720.html】
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询