Question

由键盘输入三个数，计算以这三个数为边长的三角形面积， C语言编程题，求答案

Answer 1

#include <stdio.h>

#include <math.h>

int main()

{float a,b,c,p,s;

scanf("%f%f%f",&a,&b,&c);

if(a>=b+c||b>=a+c||c>=a+b)

printf("不能构成三角形!\n");

else

{p=(a+b+c)/2;

s=sqrt(p*(p-a)*(p-b)*(p-c));  

printf("s=%g\n",s);

}

return 0;

}

Answer 2

#include <stdio.h>
#include <math.h>

int main()
{
float a, b, c, p, s;
scanf("%f%f%f", &a, &b, &c);
p = 0.5 * (a + b + c);
s = sqrt(p * (p-a) * (p-b) * (p-c));
printf("area = %f\n", s);
return 0;
}