因式分解：-(x²-y²)(x+y)-(y-x)³
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-(x²-y²)(x+y)-(y-x)³
=-(x-y)(x+y)²+(x-y)(x-y)²
=(x-y)[(x-y)²-(x+y)²]
=(x-y)(x-y+x+y)(x-y-x-y)
=-4xy(x-y)
=-(x-y)(x+y)²+(x-y)(x-y)²
=(x-y)[(x-y)²-(x+y)²]
=(x-y)(x-y+x+y)(x-y-x-y)
=-4xy(x-y)
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