Question

python 判断字符串是否有中文

Answer 1

#!/usr/bin/env python
# -*- coding:GBK -*- 

"""汉字处理的工具:
判断unicode是否是汉字，数字，英文，或者其他字符。
全角符号转半角符号。"""



def is_chinese(uchar):

        """判断一个unicode是否是汉字"""

        if uchar >= u'/u4e00' and uchar<=u'/u9fa5':

                return True

        else:

                return False

def is_number(uchar):

        """判断一个unicode是否是数字"""

        if uchar >= u'/u0030' and uchar<=u'/u0039':

                return True

        else:

                return False

def is_alphabet(uchar):

        ""绝高"判断一个unicode是否是英文字母"""

        if (uchar >= u'/u0041' and uchar<=u'/u005a') or (uchar >= u'/u0061' and uchar<=u'/u007a'):

                return True

   拿樱     else:

                return False

def is_other(uchar):

        """判断是否非汉字，数字和英文字符"""

        if not (is_chinese(uchar) or is_number(uchar) or is_alphabet(uchar)):

                return True

        else:

                return False

def B2Q(uchar):

        """半角转全角"""

        inside_code=ord(uchar)

        if inside_code<0x0020 or inside_code>0x7e:      #不是半角字符就返回原来的字符

                return uchar

        if inside_code==0x0020: #除了空格其他的全角半角的公式为:半角=全角-0xfee0

                inside_code=0x3000

        else:

                inside_code+=0xfee0

        return unichr(inside_code)

def Q2B(uchar):

        """全角转半角"""

        inside_code=ord(uchar)

        if inside_code==0x3000:

                inside_code=0x0020

        else:

                inside_code-=0xfee0

        if inside_code<0x0020 or inside_code>0x7e:      #转完之后不是半角字符返回原来的字符

                return uchar

        return unichr(inside_code)

def stringQ2B(ustring):

        """把字符串全角转半角"""

        return "".join([Q2B(uchar) for uchar in ustring])

def uniform(ustring):

        """格式化字符串，完成全角转半角，大写转小写的工作"""

        return stringQ2B(ustring).lower()

def string2List(ustring):

        """将ustring按照中文，字母，数字分开"""

        retList=[]

        utmp=[]

        for uchar in ustring:

                if is_other(uchar):

                        if len(utmp)==0:

      消宏丛                          continue

                        else:

                                retList.append("".join(utmp))

                                utmp=[]

                else:

                        utmp.append(uchar)

        if len(utmp)!=0:

                retList.append("".join(utmp))

        return retList

if __name__=="__main__":

        #test Q2B and B2Q

        for i in range(0x0020,0x007F):

                print Q2B(B2Q(unichr(i))),B2Q(unichr(i))


        #test uniform

        ustring=u'中国 人名a高频A'

        ustring=uniform(ustring)

        ret=string2List(ustring)

        print ret
顶
0

Answer 2

可以通过汉字字符的范围来判断

#-*- coding:utf-8 -*-

import sys
reload(sys)
sys.setdefaultencoding('utf8')

def check_contain_chinese(check_str):
    for ch in check_str.decode('utf-8'):
    蠢芹    if u'\u4e00' <= ch <= u'\u9fff':
            return True
    return False

if __name__ 带闭毕== "__main__":
    print check_contain_chinese('中国')
    print check_contain_chinese('xxx')
    print check_contain_chinese('xx中国')

结果：
True
False
True

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Answer 3

直接用==比粗蠢较if "相等"举凳厅=="相等": print(”相正隐等")else: print("不等")