Question

请教VC高手 ShellExecute函数问题

请教VC高手，在应用ShellExecute函数时
ShellExecute(this>m_hWnd,"open","c:\linez.exe",NULL,NULL,SW_SHOW);

其中 第三个参数 c:\linez.exe 只在一级（根目录下能被启动起来）再多一级目录遍启动不起来了，请教高手是何缘故，有礼了！
下面是一个最简单的MFC程序中的函数：
void CMy1212View::OnLButtonDblClk(UINT nFlags, CPoint point)
{
// TODO: Add your message handler code here and/or call default

char shell[]="c:\ots\ben\lyk6";
LPCTSTR lpFile;
lpFile=(LPCTSTR)shell;

// lpFile[13]="C:\linez.exe" ;
// ShellExecute(this->m_hWnd,"open","C:\linez.exe",NULL,NULL,SW_SHOW);
// ShellExecute(this->m_hWnd,"open","c:\linez.exe",NULL,NULL,SW_SHOW);
// ShellExecute(this->m_hWnd,"open","c:\lyk6",NULL,NULL,SW_SHOW);
ShellExecute(this->m_hWnd,"open",lpFile,NULL,NULL,SW_SHOW);
CView::OnLButtonDblClk(nFlags, point);
}

Answer 1

不可能,应该写为：
char shell[] = "c:\\ots\\ben\\lyk6\\linez.exe";