定积分,谢谢!
展开全部
f(x)= x|x|
f(-x) = -f(x)
∫(-π/2->π/2) [ x|x| - (cosx)^4 ] dx
=∫(-π/2->π/2) x|x| dx- ∫(-π/2->π/2) (cosx)^4 dx
=0 -∫(-π/2->π/2) (cosx)^4 dx
=-2∫(0->π/2) (cosx)^4 dx
=-(1/2)∫(0->π/2) (1+cos2x)^2 dx
=-(1/2)∫(0->π/2) [1+2cos2x+ (cos2x)^2] dx
=-(1/4)∫(0->π/2) ( 3+4cos2x+ cos4x ) dx
=-(1/4) [ 3u+2sin2x+ (1/4)sin4x ] |(0->π/2)
=-(3/8)π
f(-x) = -f(x)
∫(-π/2->π/2) [ x|x| - (cosx)^4 ] dx
=∫(-π/2->π/2) x|x| dx- ∫(-π/2->π/2) (cosx)^4 dx
=0 -∫(-π/2->π/2) (cosx)^4 dx
=-2∫(0->π/2) (cosx)^4 dx
=-(1/2)∫(0->π/2) (1+cos2x)^2 dx
=-(1/2)∫(0->π/2) [1+2cos2x+ (cos2x)^2] dx
=-(1/4)∫(0->π/2) ( 3+4cos2x+ cos4x ) dx
=-(1/4) [ 3u+2sin2x+ (1/4)sin4x ] |(0->π/2)
=-(3/8)π
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
定积分,谢谢!
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询