Question

1/√(x^2-1)积分怎么求

1/√(x^2-1)积分怎么求

Answer 1

如图所示

Answer 2

1/√(x^2-1)
令x=sect x^2-1=(tant)^2 dx=tantsectdt
∫1/√(x^2-1)dx=∫sectdt=ln|sect+tant|+C
=ln|x+√(x^2-1)|+C|