Question

12÷7+10÷11+14÷7+12÷11+16÷7,计算过程？

Answer 1

解:

12÷7+10÷11+14÷7+12÷11+16÷7

=(12÷7+14÷7+16÷7)+(10÷11+12÷11)

=(12+14+16)÷7+(10+12)÷11

=42÷7+22÷11

=6+2

=8

Answer 2

计算过程是先算除法再算加法，

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12÷7+10÷11+14÷7+12÷11+16÷7≈1.71+0.9+2+1.09+2.29≈7.99

Answer 3

12÷7=12/7 读作：七分之十二
10÷11=10/11 读作：十一分之十
12÷11=12/11 读作：十一分之十二
16÷7=16/7 读作：二七分之十六
因为这些出来都是无限小数，所以就根据“被除数÷除数=被除数/除数”（读作：被除数除以除数等于除数分之被除数）

Answer 4

12÷7+10÷11+14÷7+12÷11+16÷7
=(12+14+16)÷7+(10+12)÷11
=42÷7+22÷11
=6+2
=8