定积分∫|1-x|dx [上限为5下限为0]
展开全部
∫|1-x|dx [上限为5下限为0]
=∫(1-x)dx [上限为1下限为0]+∫(x-1)dx [上限为5下限为1]
=[x-x^2/2][上限为1下限为0]+[x^2/2-x] [上限为5下限为1]
=1-1/2+25/2-5-1/2+1
=17/2
=∫(1-x)dx [上限为1下限为0]+∫(x-1)dx [上限为5下限为1]
=[x-x^2/2][上限为1下限为0]+[x^2/2-x] [上限为5下限为1]
=1-1/2+25/2-5-1/2+1
=17/2
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询