计算：x+1/x-1+(x^3-3x+4)/(1-x^2) x加 x减1分之1 加 1-x的平方分之x的三次方减3x加4
计算：x+1/x-1+(x^3-3x+4)/(1-x^2) x加 x减1分之1 加 1-x的平方分之x的三次方减3x加4
3/(x+1)
1、(x的三次方分之1-x的平方分之1)·x-1分之x的三次方 2、2-x分之x-x的平方+4x+4分之4-x的平方
(x的三次方分之1-x的平方分之1)·x-1分之x的三次方
=(1/x³-1/x²) × x³/(x-1)
=（1/x³-x/x³)× x³/(x-1)
=(1-x)/x³× x³/(x-1)
=-(x-1)/x³× x³/(x-1)
=-1
2-x分之x-x的平方+4x+4分之4-x的平方
=x/(2-x)-(4-x²)/(x²+4x+4)
=x/(2-x)-(2+x)(2-x)/(x+2)²
=x/(2-x)-(2-x)/(x+2)
=x(x+2)/(2-x)(x+2)-(2-x)(2-x)/(x+2)(2-x)
=[(x²+2x)-(4-4x+x²)]/(2-x)(x+2)
=(x²+2x-4+4x-x²)/(x+2)(2-x)
=(6x-4)/(x+2)(2-x)
化简，求值：（x的平方-1分之x-4)除(x的平方加2x加1分之x的平方减3x减4)加x减1/1，x=2倍根号3加1
[(x-4)/(x^2-1)]÷[(x^2-3x-4)/(x^2+2x+1)]+1/(x-1)
=[(x-4)/(x+1)(x-1)]÷[(x-4)(x+1)/(x+1)^2]+1/(x-1)
=[(x-4)/(x+1)(x-1)]÷[(x-4)/(x+1)]+1/(x-1)
=(x-4)(x+1)/[(x+1)(x-1)(x-4)]+1/(x-1)
=1/(x-1)+1/(x-1)
=2/(x-1)
=2/(2√3+1-1)
=2/(2√3)
=1/√3
=√3/3
X-(1-X分之1+X平方-1分之X立方-3X+1)/(4-X平方)
x-[1/(1-x)+(x^3-3x+1)/(x^2-1)]/(4-x^2)
=x-[-1/(x-1)+(x^3-3x+1)/(x^2-1)]/(4-x^2)
=x-[-(x+1)/(x-1)(x+1)+(x^3-3x+1)/(x-1)(x+1)]/(4-x^2)
=x-{[-(x+1)+(x^3-3x+1)]/(x-1)(x+1)}/(4-x^2)
=x-{[-x-1+x^3-3x+1]/(x-1)(x+1)}/(4-x^2)
=x-{[x^3-4x]/(x-1)(x+1)}/(4-x^2)
=x+{[x^3-4x]/(x-1)(x+1)}/(x^2-4)
=x+{x[x^2-4]/(x-1)(x+1)}/(x^2-4)
=x+x/(x-1)(x+1)
=x+x/(x-1)(x+1)
=x(x-1)(x+1)/(x-1)(x+1)+x/(x-1)(x+1)
=x(x^2-1)/(x-1)(x+1)+x/(x-1)(x+1)
=(x^3-x)/(x-1)(x+1)+x/(x-1)(x+1)
=(x^3-x+x)/(x-1)(x+1)
=x^3/(x-1)(x+1)
=x^3/(x^2-1)
x的三次方减3x+1=0 求x的平方+x的平方分之1?
X平方+3X+1=0
两边除以x，
x+3+ 1/x=0
x+ 1/x =-3,
两边平方
x^2 +1/x^2 +2=9,
x^2 +1/x^2=9-2=7
x-（1-x）分之3-（x的平方-1）分之（x的三次方-x的平方+2）
=x+3/(x-1)-(x³-x²+2)/(x+1)(x-1)
=[x(x²-1)+3(x+1)-(x³-x²+2)]/(x+1)(x-1)
=(x³-x+3x+3-x³+x²-2)/(x+1)(x-1)
=(x²+2x+1)/(x+1)(x-1)
=(x+1)²/(x+1)(x-1)
=(x+1)/(x-1)
【（1-x）分之1】-1=（1-x的平方）分之（3x-x的平方）
原方程可化为2x的平方-2x=0，
解得x=0或1
又因为x-1(分母）不能为0，
所以x不为一
x等于0.
1/x+1/2x+1/3x=1计算 x分之1+2x分之1+3x分之1
1/x+1/2x+1/3x=1
6/6x+3/6x+2/6x=1
11/6x=1
x=11/6
经检验x=11/6是方程的解
计算x减1-x分之一减x方减一分之x立方减3x加1等于
你这个描述很不清楚，我建议，如果只有分数你可以用 / 来表示分数线，这样你输入就能表达你的意思了！
当x=2009时，（3x三次方-4x平方）/x+(1-x)*3x 的值
=x²(3x-4)/(x+3x-3x²)
=x²(3x-4)/[-x(3x-4)]
=-x
=-2009
