Question

已知(3-y-4x)^2;+(4x+y-3)=0,求实数x,y的值?

已知(3-y-4x)^2;+(4x+y-3)=0,求实数x,y的值?
不要转！

Answer 1

(3-y-4x)^2;+(4x+y-3)=0
(3-y-4x)^2;-(3-y-4x)=0
(3-y-4x)(2-y-4x)=0
3-y-4x=0或2-y-4x=0
只要满足3-y-4x=0或2-y-4x=0的实数x,y均符合题意要求
所以,本题有无数多解

Answer 2

先展开
16x^2+8xy+y^2-20x-5y+6=0
(4x+y)^2-5(4x+y)+6=0
(4x+y-2)(4x+y-3)=0
则4x+y=2或4x+y=3

所以不能求出定值，只能得到上述x与y的关系

Answer 3

(4x+y-3)^2+(4x+y-3)=0
(4x+y-3)(4x+y-2)=0
4x+y=3或者4x+y=2

Answer 4

(3-y-4x)^2+(4x+y-3)=0即[-(4x+y-3)]^2+(4x+y-3)=0,,(4x+y-3)^2+(4x+y-3)=0

,,(4x+y-3)^2=-(4x+y-3),,则4x+y-3=0,,或4x+y-3=-1,,

不缺条件么,?