Question

求一个c语言编程，题目是“求一个3x3矩阵对角线元素之和”

Answer 1

#include <stdio.h>枯如
main()
{
int a[3][3]={1,3,3,2,4,3,5,3,2};
int i,j;
int sum=0;
printf("\稿顷n");
for(i=0;i<3;i++)
{
printf("\n");
for(j=0;j<3;j++)
printf("%5d",a[i][j]);
}
printf("\n");
for(i=0;i<3;i++)
sum=sum+a[i][2-i];
for(i=0;i<3;i++)
sum=sum+a[i][i];
sum=sum-a[3/2][3/2];
printf("\没敬启n%d",sum);
}

Answer 2

#include<stdio.h>
int main()
{
int i,sum=0,a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; /扰漏兆/3x3矩阵
for (i=0;i<3;i++) sum=sum+a[i][i];
printf("搜档对角线元素和=%d\缓租n",sum);
return 0;
}

Answer 3

计划该机构