帮忙数学题
2个回答
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(1)(x-1)/(x²+3x+2)+6/(2+x-x²)-(10-x)/(4-x²)
=(x-1)/(x²+3x+2)-6/(x²-x-2)+(10-x)/(x²-4)
=(x-1)/(x+1)(x+2)-6/(x+1)(x-2)+(10-x)/(x+2)(x-2)
=(x-1)(x-2)/(x+1)(x+2)(x-2)-6(x+2)/(x+1)(x+2)(x-2)+(10-x)(x+1)/(x+1)(x+2)(x-2)
=【(x²-3x+2)-6(x+2)+(9x+10-x²)】/(x+1)(x+2)(x-2)
=(x²-3x+2-6x-12+9x+10-x²)/(x+1)(x+2)(x-2)
=0/(x+1)(x+2)(x-2)
=0
(2)【x+1-1/(1-x)】÷【x-x²/(x-1)】
=【x+1+1/(x-1)】÷【x(x-1)/(x-1)-x²/(x-1)】
=【(x+1)(x-1)/(x-1)+1/(x-1)】÷【(x²-x-x²)/(x-1)】
=【(x²-1+1)/(x-1)】÷【(-x)/(x-1)】
=【x²/(x-1)】×【-(x-1)/x】
=-x
=(x-1)/(x²+3x+2)-6/(x²-x-2)+(10-x)/(x²-4)
=(x-1)/(x+1)(x+2)-6/(x+1)(x-2)+(10-x)/(x+2)(x-2)
=(x-1)(x-2)/(x+1)(x+2)(x-2)-6(x+2)/(x+1)(x+2)(x-2)+(10-x)(x+1)/(x+1)(x+2)(x-2)
=【(x²-3x+2)-6(x+2)+(9x+10-x²)】/(x+1)(x+2)(x-2)
=(x²-3x+2-6x-12+9x+10-x²)/(x+1)(x+2)(x-2)
=0/(x+1)(x+2)(x-2)
=0
(2)【x+1-1/(1-x)】÷【x-x²/(x-1)】
=【x+1+1/(x-1)】÷【x(x-1)/(x-1)-x²/(x-1)】
=【(x+1)(x-1)/(x-1)+1/(x-1)】÷【(x²-x-x²)/(x-1)】
=【(x²-1+1)/(x-1)】÷【(-x)/(x-1)】
=【x²/(x-1)】×【-(x-1)/x】
=-x
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