
展开全部
sinx+cosx=t
-√2<=t<=√2
y=sinx+cosx+sinxcosx
=t+1/2(t^2-1)
=1/2(t+1)^2-1
x=2k∏+∏/4,t=√2最大值(2√2+1)/2
x=2k∏-∏/2],t=-1最小值-1
值域[-1,(2√2+1)/2]
-√2<=t<=√2
y=sinx+cosx+sinxcosx
=t+1/2(t^2-1)
=1/2(t+1)^2-1
x=2k∏+∏/4,t=√2最大值(2√2+1)/2
x=2k∏-∏/2],t=-1最小值-1
值域[-1,(2√2+1)/2]
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询