Question

已知a,b为实数,且b=根号1-4a+根号4a-1+1/2，求根号a/b+2+b/a-根号a/b-2+b/a的值

Answer 1

解析：∵1-4a≥0,4a-1≥0∴1-4a=0,得a=1/4
∴ b=1/2,
√液链(a/b+2+b/a)-√(a/b-2+b/a)
=√[√(a/清埋芦b)+√(b/a)]^2-)-√[√(a/b)-√(b/a)]^2
=√(a/b)+√(b/a)-√(b/a)+√(a/答带b)
=2√(a/b)
则原式=2*√[（1/4)/(1/2)]=√2