lim(x趋于1)(x²–1/x–1)乘以e的1/x–1次方=
展开全部
简单分析一下，答案如图所示
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
展开全部
lim [(x²-1)/(x-1)]·e^[1/(x-1)]
x→1⁺
=lim [(x+1)(x-1)/(x-1)]·e^[1/(x-1)]
x→1⁺
=lim (x+1)·e^[1/(x-1)]
x→1⁺
=2·e^(+∞)
=+∞
lim [(x²-1)/(x-1)]·e^[1/(x-1)]
x→1⁻
=lim [(x+1)(x-1)/(x-1)]·e^[1/(x-1)]
x→1⁻
=lim (x+1)·e^[1/(x-1)]
x→1⁻
=2·e⁰
=2
[(x²-1)/(x-1)]·e^[1/(x-1)]在x=1处两侧极限不相等
lim [(x²-1)/(x-1)]·e^[1/(x-1)] 不存在
x→1
x→1⁺
=lim [(x+1)(x-1)/(x-1)]·e^[1/(x-1)]
x→1⁺
=lim (x+1)·e^[1/(x-1)]
x→1⁺
=2·e^(+∞)
=+∞
lim [(x²-1)/(x-1)]·e^[1/(x-1)]
x→1⁻
=lim [(x+1)(x-1)/(x-1)]·e^[1/(x-1)]
x→1⁻
=lim (x+1)·e^[1/(x-1)]
x→1⁻
=2·e⁰
=2
[(x²-1)/(x-1)]·e^[1/(x-1)]在x=1处两侧极限不相等
lim [(x²-1)/(x-1)]·e^[1/(x-1)] 不存在
x→1
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
