Question

获得Servlet初始化参数

<servlet>
<servlet-name>JDBCServlet</servlet-name>
<servlet-class>com.test.JDBCServlet</servlet-class>
<init-param>
<param-name>DRIVER</param-name>
<param-value>com.microsoft.jdbc.sqlserver.SQLServer</param-value>
</init-param>
<init-param>
<param-name>URL</param-name>
<param-value>jdbc:microsoft.sqlserver://127.0.0.1:1433;DatabaseName=testjsp</param-value>
</init-param>
<init-param>
<param-name>USER</param-name>
<param-value>root</param-value>
</init-param>
<init-param>
<param-name>PASSWORD</param-name>
<param-value>123456</param-value>
</init-param>
<servlet>
.....
<servlet-mapping>
<servlet-name>JDBCServlet</servlet-name>
<url-pattern>/init_servlet</url-pattern>
</servlet-mapping>

public void init()throws ServletException{
driver=getInitParameter("DRIVER");
password=getInitParameter("PASSWORD");
url=getInitParameter("URL);
user=getInitParameter("USER");
}

这是我配置的运行的时候不知道哪错了

at javax.servlet.GenericServlet.getInitParameter(GenericServlet.java:100)
at mypackage.servletrequest.init(servletrequest.java:88)
at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1173)
at org.apache.catalina.core.StandardWrapper.allocate(StandardWrapper.java:809)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:129)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:857)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588)
at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
at java.lang.Thread.run(Thread.java:619)
init
2010-7-24 21:21:24 org.apache.catalina.startup.HostConfig checkResources

Answer 1

有句比较重要的信息你没有贴出来哦..就是他到底报的什么异常哦..

Answer 2

楼主你好，我不知道你的servlet代码是否是用开发工具写的，也不能确定你的代码粘贴的时候是否准确。
就目前而言，我发现了两个问题：
第一个，xml文件里,
<init-param>
<param-name>PASSWORD</param-name>
<param-value>123456</param-value>
</init-param>
<servlet> ,
<servlet> 在这里应该是结束符，你少了个/，正确的应该是</servlet>。
第二个，init()方法里，url=getInitParameter("URL);这个语法错误了吧，应该是url = getInitParameter("URL"); 你的参数后面少了个"。
你把这两个问题改了，应该不会出错了。