Question

Parse error: syntax error, unexpected '$result' (T_VARIABLE) in 。。。.php on line

Parse error: syntax error, unexpected '$result' (T_VARIABLE) in C:\wamp\www\chengjixiugai.php on line 7
<?
session_start();$conn=mysql_connect("localhost","root","");
mysql_query("set names 'gb2312'");
mysql_select_db("student",$conn);
$sno=intval ($_GET['sno']);
$sql="SELECT * FROM `xueshengcj` where sno=$sno and cno=15"
$result =mysql_query($sql,$conn);
$row=mysql_fetch_assoc($result);
?>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" >
<h1 align="center">修改学生成绩</h1>
<form method= "post"action="xiugaixueshengxinxi.php?sno=<? =$row['sno']?>">
<table width="400"border="1"align="center"cellpadding="2">
<tr><td width="125">学号：</td>
<td width="275"><input type="text"name="sno"value="">*</td></tr>
<tr><td>课程编号：</td>
<td><input type ="text" name="cno"value="" >*</td></tr>
<tr><td>课程名：</td>
<td><input type="text" name="cname"value="" >*</td></tr>
<tr><td>成绩：</td>
<td><input type="text" name="mark"value="" >*</td></tr>
<tr><td> </td><td><input type="submit"value="确定" ></td></tr>
</table>
</form>

Answer 1

$result =mysql_query($sql,$conn);这里没有查到数据集

Answer 2

少个；