Question

C语言求完数因子

C语言求完数因子我想输出的格式比如6 is factors are 1，2，3
28 is factors are ，，，，，
496 is ，，，，，，

Answer 1

#include<stdio.h>
int a[110];
int main()
{
    int sum=0,i,n,j,sizes;
    printf("输入一个数：");
    scanf("%d",&n);
    for(i=1; i<=n; i++)
    {
        sum=0,sizes=0;
        for(j=1; j<i; j++)
        {
            if(i%j==0)
            {
                sum+=j;
                a[++sizes]=j;
            }
        }
        if(sum==i)
        {
            printf("%d is factors are:",i);
            for(j=1;j<=sizes;j++)
                printf(j==sizes?"%d.\n":"%d,",a[j]);
        }
    }
    return 0;
}

开个数组储存一下因子即可。