第六题的解题思路和过程
1个回答
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由题意可知,sin(x)在[-π/2,π/2]内为增函数,在[π/2,3π/2]内为减函数。
-π/6<=X<=a
-3^0.5/2<=sin(X-π/6)<=1……1式
对于1式,分情况讨论:
1)当-π/2<=X-π/6<=π/2内,即x在[-π/3,2π/3]内
-π/3<=X-π/6<=π/2
解出:-π/6<=X<=2π/3
a(min)的取值为2π/3
2)当π/2<=X-π/6<=3π/2内,即x在[2π/3,5π/3]内
-π/3<=π-(X-π/6)<=π/2
解出2π/3<=X<=3π/2
-π/6<=X<=a
a(max)的取值为a=3π/2
综合上述
所以a的取值为2π/3<=a<=3π/2
-π/6<=X<=a
-3^0.5/2<=sin(X-π/6)<=1……1式
对于1式,分情况讨论:
1)当-π/2<=X-π/6<=π/2内,即x在[-π/3,2π/3]内
-π/3<=X-π/6<=π/2
解出:-π/6<=X<=2π/3
a(min)的取值为2π/3
2)当π/2<=X-π/6<=3π/2内,即x在[2π/3,5π/3]内
-π/3<=π-(X-π/6)<=π/2
解出2π/3<=X<=3π/2
-π/6<=X<=a
a(max)的取值为a=3π/2
综合上述
所以a的取值为2π/3<=a<=3π/2
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