急 [ln^3(x^2)+3]' 求导？
1个回答
展开全部
令a=ln(x^2)
则先对a^3求导,再对ln求导,最后对x^2求导
所以[ln^3(x^2)+3]'
=[ln^3(x^2)]'
=3[ln(x^2)]^2*[ln(x^2)]'
=3[ln(x^2)]^2*(1/x^2)*(x^2)'
=6x[ln(x^2)]^2*(1/x^2)
=(6/x)*[ln(x^2)]^2,2,3ln^2(x^2)*(1/(x^2))*2x,0,
则先对a^3求导,再对ln求导,最后对x^2求导
所以[ln^3(x^2)+3]'
=[ln^3(x^2)]'
=3[ln(x^2)]^2*[ln(x^2)]'
=3[ln(x^2)]^2*(1/x^2)*(x^2)'
=6x[ln(x^2)]^2*(1/x^2)
=(6/x)*[ln(x^2)]^2,2,3ln^2(x^2)*(1/(x^2))*2x,0,
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
