Question

在js中如何取出json中的对象的值

现有一个从PHP端返回的json（变量名为gets）：
{"code":0,"data":[{"uid":"689791","username":"vaghyuzhihao","orgid":"627","status":"1","subname":"yuzhihao","roleids":"1","orgcode":"600251","name":"yuzhihao","mapid":"0","passwd":"","siteid":"0","createorgcode":"600251","alarmview":"0"}]}
请取出data中uid的值

我是这么写的：alert(gets.uid);
返回的是undefined
请问该怎么取 在线等！

Answer 1

二楼少了个括号

var json = eval("("+str+")");

Answer 2

你这个是个字符串。JSON.parse一下就行了

Answer 3

var str = {"code":0,"data":[{"uid":"689791","username":"vaghyuzhihao","orgid":"627","status":"1","subname":"yuzhihao","roleids":"1","orgcode":"600251","name":"yuzhihao","mapid":"0","passwd":"","siteid":"0","createorgcode":"600251","alarmview":"0"}]};
var json = eval(str);
console.log(json.data[0].uid);

一般返回的都是字符串，需要对其对象化

追问

我照你说的做了一下，还是这样的提示

其实alert未处理过的变量时，是一个object，不是string，不用处理也可以，就是找不到uid的值，疯掉了，大神！若何破....

追答

var json;
var str = {"code":0,"data":[{"uid":"689791","username":"vaghyuzhihao","orgid":"627","status":"1","subname":"yuzhihao","roleids":"1","orgcode":"600251","name":"yuzhihao","mapid":"0","passwd":"","siteid":"0","createorgcode":"600251","alarmview":"0"}]};
if(typeof str === 'object'){
json = str;
}
else{
json = eval(str);
}
console.log(json.data[0].uid);

试试这个，判断输入的是否为object，是则直接输出，不是则将其转换成object再输出

Answer 4

你前台是用什么接收的？

追问

js

追答

2楼正解！