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3x^2-2ax+2a-3
=3(x-a/3)^2-a^2/3+2a-3
=3(x-a/3)^2-(1/3)(a^2-6a+9)
=3(x-a/3)^2-(1/3)(a-3)^2
=(1/3)(3x-a)^2-(1/3)(a-3)^2
=(1/3)[(3x-a)+(a-3)][(3x-a)-(a-3)]
=(1/3)(3x-3)(3x-2a+3)
=(x-1)(3x-2a+3)
3x^2-2ax+2a-3
=3x^2-3-2a(x-1)
=3(x+1)(x-1)-2a(x-1)
=(x-1)(3x+3-2a)
=3(x-a/3)^2-a^2/3+2a-3
=3(x-a/3)^2-(1/3)(a^2-6a+9)
=3(x-a/3)^2-(1/3)(a-3)^2
=(1/3)(3x-a)^2-(1/3)(a-3)^2
=(1/3)[(3x-a)+(a-3)][(3x-a)-(a-3)]
=(1/3)(3x-3)(3x-2a+3)
=(x-1)(3x-2a+3)
3x^2-2ax+2a-3
=3x^2-3-2a(x-1)
=3(x+1)(x-1)-2a(x-1)
=(x-1)(3x+3-2a)
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