如图,求解,求具体过程
1个回答
2016-06-11
展开全部
GMm/r²=mg
M=g'R^2/G
M=ρV=ρ*(4/3)πR^3
ρ*(4/3)πR^3=g'R^2/G
ρ=(3g')/(4πGR)
GMm/r²=m(2π/T)²r
M=4π^2*R^3/(G*T^2)
M=ρV=ρ*(4/3)πR^3
ρ*(4/3)πR^3=4π^2*R^3/(G*T^2)
ρ=3π/G*T^2
望采纳,谢谢!
M=g'R^2/G
M=ρV=ρ*(4/3)πR^3
ρ*(4/3)πR^3=g'R^2/G
ρ=(3g')/(4πGR)
GMm/r²=m(2π/T)²r
M=4π^2*R^3/(G*T^2)
M=ρV=ρ*(4/3)πR^3
ρ*(4/3)πR^3=4π^2*R^3/(G*T^2)
ρ=3π/G*T^2
望采纳,谢谢!
追问
第三点呢
追答
哪个第三点?
是说第三小题?
GMm/r²=m(2π/T)²r
M=4π^2*R^3/(G*T^2)
M=ρV=ρ*(4/3)πR^3
ρ*(4/3)πR^3=4π^2*R^3/(G*T^2)
ρ=3π/(G*T^2)
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