Question

谁来帮我分解一下这个因式！！急！！！

(2x^2-3x+1)^2-22x^2+33x-1

x^4-7x^2+1

Answer 1

(2x^2-3x+1)^2-22x^2+33x-1
=(2x^2-3x+1)^2-11(2x^2-3x+1)+10
把(2x^2-3x+1)看成y,
上式=y^2-11y+10=(y-1)(y-10)
把y的值代人得：
(2x^2-3x+1)^2-22x^2+33x-1
=(2x^2-3x)(2x^2-3x-9)
=x(2x-3)(2x+3)(x-3)
2)
x^4-7x^2+1
=x^4-2x^2+1-5x^2
=(x^2-1)^2-(√5x)^2
=(x^2-1+√5x)(x^2-1-√5x)
=(x^2+√5x-1)(x^2-√5x-1)

Answer 2

我要指正 winelover72第二题应有理分解
1.(2x^2-3x+1)^2-22x^2+33x-1
=(2x^2-3x+1)^2-22x^2+33x-11+10
=(2x^2-3x+1)^2-11(2x^2-3x+1)+10
=x(x-3)(2x-3)(2x+3)
2.x^4-7x^2+1
=x^4+2x^2+1-9x^2
=(x^2+1)^2-(3x)^2
=(x^2-3x+1)(x^2+3x+1)

Answer 3

1.

2.
(x^2-7/2)^2 - 45/4

Answer 4

上下是一个因式吗？