Question

一道英文物理题。请高手帮忙解答。要步骤。

A police car at rest, passed by a speeder travelling at a constant 96 km h-1, takes off in hot pursuit. The police officer catches up to the speeder in 750 m, maintaining a constant acceleration.
Calculate the length of time it takes (in seconds) for the police officer to overtake the speeder.

Answer 1

一辆警车静止不动，一辆以96 km h-1匀速运动的快车经过，警车立即追赶。加速度不变经过了750 m后追上了快速行驶的车辆。
计算警车追上这辆车所需时间（s）。
解：96 km h-1=80/3 m·s-1
t=750/(80/3)=28.125 s

Answer 2

巡逻车静止不懂， 一辆一每小时96千米的经过
警车以一个军加速运动在750米处追上这辆车

计算出警车追上这辆车所用的时间的时间（用秒为单位）