因式分解:X(X+1)(X+2)(X+3)+1
2个回答
展开全部
x(x+1)(x+2)(x+3)+1
=[x(x+3)][(x+1)(x+2)]+1
=(x²+3x)(x²+3x+2)+1
=(x²+3x)²+2(x²+3x)+1
=(x²+3x+1)²
=[x(x+3)][(x+1)(x+2)]+1
=(x²+3x)(x²+3x+2)+1
=(x²+3x)²+2(x²+3x)+1
=(x²+3x+1)²
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展开全部
x(x+1)(x+2)(x+3)+1
=[x(x+3)][(x+1)(x+2)]+1
=(x²+3x)(x²+3x+2)+1
=(x²+3x)²+2(x²+3x)+1
=(x²+3x+1)²
=[x(x+3)][(x+1)(x+2)]+1
=(x²+3x)(x²+3x+2)+1
=(x²+3x)²+2(x²+3x)+1
=(x²+3x+1)²
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