求数学大神解答一下这题,最后要用分数和派表示这怎么算呀?谢谢了
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陀螺型,下面是尖的,上面是平的,圆,侧面是立方曲线
y=(5x)^(1/3),5x=y³,x=y³/5,
ds=√(dx²+dy²)=√(x'²+1)dy
x'=3y²/5
侧面积=∫(0,5)2πxds
=∫(0,5)2πx√(x'²+1)dy
=2π∫(0,5)(y³/5)√(9y^4/25+1)dy
=2π/25∫(0,5)(y³)√(9y^4+25)dy
=2π/100∫(0,5)√(9y^4+25)dy^4
=6π/100∫(0,5)√(y^4+25/9)d(y^4+25/9)
=(π/25)[(y^4+25/9)^(3/2)](0,5)
=(π/25)[(5^4+25/9)^(3/2)-(25/9)^(3/2)]
=(π/25)[((25×9+1)25/9)^(3/2)-(5/2)³]
=(π/25)[226^(3/2)-1](5/2)³
=(5π/8)[226^(3/2)-1]
y=(5x)^(1/3),5x=y³,x=y³/5,
ds=√(dx²+dy²)=√(x'²+1)dy
x'=3y²/5
侧面积=∫(0,5)2πxds
=∫(0,5)2πx√(x'²+1)dy
=2π∫(0,5)(y³/5)√(9y^4/25+1)dy
=2π/25∫(0,5)(y³)√(9y^4+25)dy
=2π/100∫(0,5)√(9y^4+25)dy^4
=6π/100∫(0,5)√(y^4+25/9)d(y^4+25/9)
=(π/25)[(y^4+25/9)^(3/2)](0,5)
=(π/25)[(5^4+25/9)^(3/2)-(25/9)^(3/2)]
=(π/25)[((25×9+1)25/9)^(3/2)-(5/2)³]
=(π/25)[226^(3/2)-1](5/2)³
=(5π/8)[226^(3/2)-1]
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