化简，求详细过程
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f'(x)
=x^(2/3)+2x/3·x^(-1/3)-2/3·x^(-1/3)
=x^(2/3)+2/3·x^(2/3)-2/3·x^(-1/3)
=5/3·x^(2/3)-2/3·x^(-1/3)
=(5x-2)/3·x^(-1/3)
=(5x-2)/(3·³√x)
=x^(2/3)+2x/3·x^(-1/3)-2/3·x^(-1/3)
=x^(2/3)+2/3·x^(2/3)-2/3·x^(-1/3)
=5/3·x^(2/3)-2/3·x^(-1/3)
=(5x-2)/3·x^(-1/3)
=(5x-2)/(3·³√x)
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