Question

java 剪刀石头布 这个游戏怎么用数组来实现，我把脑壳都想破了

要求 人输入的是字符“剪刀”“石头”“布” 然后与电脑做比较，判断输赢

Answer 1

import java.util.*;

public class Exam
{
public static void main(String[] args)
{
String[] cq={"石头","剪刀","布"};
String guess;
int youwin=0,mewin=0,daping=0,total=0,n;
Random r=new Random();
Scanner sc=new Scanner(System.in);

while(true)
{
n=r.nextInt(3);
System.out.print("石头、剪刀、布，我已出，请你出（输入exit退出循环）：");
guess=sc.nextLine();
if(guess.equals("exit"))
{
break;
}
else
{
total++;
System.out.print("这一次你出的是"+guess+"，我出的是"+cq[n]+"，所以");
if(guess.equals("石头")&&1==n || guess.equals("剪刀")&&2==n || guess.equals("布")&&0==n)
{
youwin++;
System.out.println("你赢了！");
}
else if(guess.equals(cq[n]))
{
daping++;
System.out.println("我们打平了！");
}
else
{
mewin++;
System.out.println("我赢了！");
}
}
}
System.out.println("总共玩了"+total+"次，你赢了"+youwin+"次，我赢了"+mewin+"次，打平"+daping+"次！");
}
}