Question

json 怎么拼接变量

<li class="bm"><img class="c-img" src="mark.jpg">
<span class="c-title">博美犬</span>

<script>
var JSONdog= {
"bm":"bm.jpg"
};
$(".pet-list li").click(function(){
var dogli=$(this).attr("class");
//console.log(dogli);
var aa=JSONdog.dogli; //这里怎么把它拼成 JSONdog.bm
$(this).find(".c-img").attr("src",aa);
})
</script>

Answer 1

var aa=JSONdog["dogli"];